4x^2-9x+3x^2+4x+10=4

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Solution for 4x^2-9x+3x^2+4x+10=4 equation: 



4x^2-9x+3x^2+4x+10=4

We move all terms to the left:

4x^2-9x+3x^2+4x+10-(4)=0

We add all the numbers together, and all the variables

7x^2-5x+6=0

a = 7; b = -5; c = +6;
Δ = b2-4ac
Δ = -52-4·7·6
Δ = -143
Delta is less than zero, so there is no solution for the equation

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